tentukan massa molekul relatif senyawa organik berikut ini a. C2H4 b. CH3OH c. CH3COOH d. C6H12O6 e. CH3COCH3 f. C12H22O11

A. C2H4
= (12.2)+(4.1)
=28 g/mol
B.CH3OH
=(12.1)+(4.1)+(16.1)
=32 g/mol
C.CH3COOH
=(12.2)+(4.1)+(16.2)
=24+4+32
=60 g/mol
D.C6H12O6
=(12.6)+(12.1)+(16.6)
= 72+12+96
=180g/mol
E. CH3COCH3
=(12.3)+(6.1)+(16.1)
= 58 g/mol
F. C12H22O11
= (12.12)+(22.1)+(16.11)
=144+22+176
=342