jika (125×27)^-2/3 =p maka 15p

Mapel Matematika
Bab Eksponen

((125 x 27)/64)^-2/3
= ((5^3 x 3^3)/4^3)^-2/3
= ((5 x 3)/4)^-2
= (4/15)^2
= 16/225

15p = 15(16/225) = 16/15

p =
[tex]( \frac{(125 \times 27)}{64}) {}^{ - \frac {2}{3} } =( \frac{64}{(125 \times 27)} ) ^{ \frac{2}{3} } [/tex]
[tex]( \frac{64}{(125 \times 27)} ) ^{ \frac{2}{3} } = ( \frac{ {4}^{3} }{( {5}^{3} \times {3}^{3} )} ) ^{ \frac{2}{3} } [/tex]
[tex] ( \frac{ {4}^{2} }{( {5}^{2} \times {3}^{2} )} ) = ( \frac{16}{(25 \times 9)} ) = \frac{16}{225} [/tex]
15p =
[tex]15 \times ( \frac{16}{225} ) = \frac{16}{15} [/tex]