persamaan garis melalui titik (4,-6) dan tegak lurus garis 2y-4x+3=0 adalah...?

Kelas 8 Matematika
Bab Persamaan Garis

ax + by + c = 0, tegak lurus, (p, q)
bx - ay - (bp - aq) = 0

-4x + 2y + 3 = 0, tegak lurus, (4, -6)
2x + 4y - (2 . 4 + 4 . -6) = 0
2x + 4y - (8 - 24) = 0
2x + 4y - (-16) = 0
2x + 4y + 16 = 0
x + 2y + 8 = 0

[tex]m1 = \frac{ - a}{b} \\ m1 = \frac{ - ( - 4)}{2} = \frac{4}{2} = 2 \\ \\ m1 \times m2 = - 1 \\ 2 \times m2 = - 1 \\ m2 = - \frac{1}{2} \\ \\ y - y1 = m(x - x1) \\ y + 6 = - \frac{1}{2} (x - 4) \\ y + 6 = - \frac{1}{2} x + 2 \\ 2y + 12 = - x + 4 \\ x + 2y + 12 - 4 = 0 \\ x + 2y + 8 = 0 \: atau \: x + 2y = - 8[/tex]