Diketqhui 3 log 2=a dan 3log5=b maka nilai dari 3log150 adalah

3log150 = 3log(3×5²×2) = 3log3 + 2. 3log5 + 3log2 = 1+2b+a


Semoga membantu^^

[tex]3log2 = a \\ \frac{log2}{log3} = a \\ log2 = alog3 \\ \\ 3log5 = b \\ \frac{log5}{log3} = b \\ log5 = blog3 \\ \\ = 3log150 \\ = \frac{log150}{log3} \\ = \frac{log(2 \times 3 \times {5}^{2}) }{log3} \\ = \frac{log2 + log3 + 2log5}{log3} \\ = \frac{alog3 + log3 + 2blog3}{log3} \\ = \frac{a + 1 + 2b}{1} \\ = 1 + a + 2b[/tex]