Integral (atas)2 (bawah) -2 (3x2+4)dx= brapa bro ada yang bisa jawab

Integral batas 2,-2 (3x^2 + 4)dx
=x^3 + 4x |2, -2
= (2^3 + 4.2) - ((-2)^3 + 4(-2)
= (8 + 8) - ( -8 - 8)
= 16 - (-16)
= 32