Nilai dari 3 log 36 + 3 log 7 . 7 log 1/4 adalah.. Beserta caranya terimakasih

[tex] {}^{3} log36 + {}^{3} log7 \times {}^{7} log \frac{1}{4} = {}^{3} log36 + {}^{3} log \frac{1}{4} = {}^{3} log(36 \times \frac{1}{4} ) = {}^{3} log9 = 2[/tex]

jawaban terlampir :)