Matematika

Pertanyaan

Hasil dari 6log 32. √8 log 27. 1/3 log 6 √6 per √2 log 32 - √2 log 8

1 Jawaban

  • [tex] = \frac{6log32. \sqrt{8} log27. \frac{1}{3} log6 \sqrt{6} }{ \sqrt{2}log32 - \sqrt{2} log8 } \\ = \frac{6log {2}^{4} . {2}^{ \frac{3}{2} }log {3}^{3}. {3}^{ - 1} log {6}^{ \frac{3}{2} } }{ {2}^{ \frac{1}{2} } log( \frac{32}{8} )} \\ = \frac{(4 \times ( 3 \div \frac{3}{2} ) \times ( \frac{3}{2} \div ( -1 ))) \times 6log2.2log3.3log6}{ {2}^{ \frac{1}{2} } log {2}^{2} } \\ = \frac{4 \times ( 3 \div \frac{3}{2} ) \times ( \frac{3}{2} \div ( -1 ))}{2 \div \frac{1}{2} } \\ = \frac{4 \times (3 \times \frac{2}{3} ) \times ( \frac{3}{2} \times ( - \frac{1}{1})) }{2 \times \frac{2}{1} } \\ = \frac{4 \times 2 \times ( - \frac{3}{2}) }{4} \\ = \frac{ - 12}{4} \\ = - 3[/tex]

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