nmr 21 in gmn caranya ya

garis a tegak lurus garis b, sehingga m(a) × m(b) = -1
m(a) = -4/6
=> -4/6 × m(b) = -1 => m(b) = -1 × (-6/4) => m(b) = 6/4

pers. garis dng gradien 6/4 dan melalui titik (2,3)
y-y1 = m(x-x1)
y-3 = 6/4 (x-2)
y-3 = 6/4x - 3
-------------------- ×4
4y-12 = 6x-12
4y-6x = 0
2y-3x = 0