mencari ph CaOH 0.001M

diketahui : Ca(OH)2 0,001 M
ditanya : pH?
jawab

Ca(OH)2 --> Ca2+ + 2OH-
valensi basa = 2

[OH-] = valensi basa × M
[OH-] = 2 × 0,001
[OH-] = 2 × 10^-3

pOH = -log[OH-]
pOH = -log2× 10^-3
pOH = 3-log2

pH = 14-(3-log2)
pH = 11+log2

semoga membantu ^^

Mapel: Kimia
Kelas: XI
Materi: Asam Basa

Jawab

Ca(OH)2 → Ca²+ + 2OH-
merupakan basa kuat
Valensi basa = 2

[OH-] = Vb × M
[OH-] = 2 × 0.001
[OH-] = 0.002
[OH-] = 2×10-³

pOH= -log[OH-]
pOH =-log 2×10-³
pOH= 3-log2

pH= 14-pH
pH= 14-(3-log2)
pH = 11+log2
pH = 11+0.3
pH= 11,3