mohon bantuannyaa (2xz^-2/3yz^-3)^-2

[tex] {( \frac{2x {z}^{ - 2} }{3y {z}^{ - 3} }) }^{ - 2} = \frac{ {2}^{ - 2} {x}^{ - 2} z {}^{4} }{ {3}^{ - 2} {y}^{ - 2} {z}^{6} } = \frac{9 {y}^{2} }{4 {x}^{2} {z}^{2} } [/tex]