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1 Jawaban

  • TITRASI ASAM BASA

    V₁ = (49 + 48 + 51 + 52) / 4 = 50 mL
    M₁ = 0,1 M
    n₁ = 1 [valensi NaOH ada 1]
    V₂ = 25 mL
    n₂ = 2

    M₂ = ???

    V₁ M₁ n₁ = V₂ M₂ n₂
    50 × 0,1 × 1 = 25 × 2 × M₂
    M₂ = 0,1 M