Matematika

Pertanyaan

the perimeter of a retangle is 54 cm. its lenght is twice its breadth. find the area of the rectangle

1 Jawaban

  • p = length; l = width
    Perimeter = 2(p x l)

    p = 2l
    Perimeter = 2(2l x l)
    54 = 2(2l
    ²) = 4l²
    54/4 = l²
    13.5 = l²
    l = √13.5

    p = 2l = 2
    √13.5

    Area = p x l = 
    √13.5 x 2√13.5 = 2 x 13.5 = 27 cm²


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