larutan asam sulfat 0,04 M sebanyak 10 liter mempunyai ph
Kimia
sjx
Pertanyaan
larutan asam sulfat 0,04 M sebanyak 10 liter mempunyai ph
2 Jawaban
-
1. Jawaban adityaputrap13p5m55w
[H+] = 2x0.04 M
= 8 x 10^-2
pH= 2 - log8
=2-0.90
= 1.1 -
2. Jawaban fajrin03
[tex](h + ) = 2 \times 0.04 \\ = 8 \times 10 {}^{2} - 2 \\ ph = 2 - log8 \\ =2 - 0.90 \\ = 1.1[/tex]