Jika titik A (-1,5,4), B (2,-1,-2), dan C (p,q,-4) segaris, nilai p^2 + q^2 =??? Mohon bntu jwb,, trima ksih

Untuk titik A, B dan C segaris, maka
AC = m. AB
[tex] \left[\begin{array}{ccc}p-(-1)\\q-5\\-4-4\end{array}\right] =m \left[\begin{array}{ccc}2-(-1)\\-1-5\\-2-4\end{array}\right] \\ \\ \left[\begin{array}{ccc}p+1\\q-5\\-8\end{array}\right] =m \left[\begin{array}{ccc}3\\-6\\-6\end{array}\right] [/tex]

-8 = -6m
m = 8/6 = 4/3

q - 5 = -6m
q = -6m + 5 = -6(4/3) + 5 = -3

p + 1 = 3m
p = 3m - 1 = 3(4/3) - 1 = 3

p² + q² = 3² + (-3)² = 9 + 9 = 18