Perhatian gambar berikut! Agar alat hidrolik dalam keadaan seimbang, besar gaya F2 adalah... Tolong jawab ya!!!

FLUIDA STATIS

[tex] \mathrm{F_1 = 10 \ N} \\
\mathrm{A_1 = 2 \ cm^2} \\
\mathrm{A_2 = 4 \ cm^2} \\
\\
\mathrm{F_2 = ???} \\
\\
\mathrm{\frac{F_1}{A_1} = \frac{F_2}{A_2} } \\
\mathrm{\frac{10}{2} = \frac{F_2}{4} } \\
\mathrm{F_2 = 5 \times 4} \\
\mathrm{F_2 = 20 \ N} [/tex]

Jawaban : A

dik : f¹ = 10 N
:A¹ = 2 cm²
:A² = 4 cm²
dit : f².....?

penyelesaian

rumus

f² = A² x f¹
_____
A¹

f² = 4 x 10
_____
2

f² = 40
___
2

f² = 20 N



jadi jawabannya a. 20 N