9log32 × 2log9 - 2log25 × 5log4 = Mohon penjelasan caranya

Kelas 10 Matematika
Bab Logaritma

⁹log 32 . ²log 9 - ²log 25 . ⁵log 4
= ⁹log 9 . ²log 32 - ²log 4 . ⁵log 25
= 1 . ²log 2⁵ - ²log 2² . ⁵log 5²
= 5 . ²log 2 - 2 . ²log 2 . 2 . ⁵log 5
= 5 - 2 . 2
= 1

9log 32 x 2log 9 - 2log 25 x 5log 4
= log 32/log 9 x log 9/log 2 - log 25/log 2 x log 4/log 5
= log 2^5/log 9 x log 9/log 2 - log 5^2/log 2 x log 2^2/log 5
= log 2^5/log 2 - 2.log 5/log 2 x 2.log 2/log 5
= 5.log 2/log 2 - 2.log 5/log 5 x 2.log 2/log 2
= 5 - 2.2
= 5 - 4
= 1