Bantuin Dong Guys???Pake penyelesaiannya!!!

[tex] \frac{8}{ \sin(90) } = \frac{x}{ \sin(30) } \\ 8 = \frac{x}{ \frac{1}{2} } \\ x = 4[/tex]
x = BD
[tex] \frac{4}{ \sin(90) } = \frac{t}{ \sin(60) } \\ 4 = \frac{t}{ \frac{ \sqrt{3} }{2} } \\ t = 2 \sqrt{3} [/tex]
t = tinggi
[ABD]= ½ X 2√3 X 8 = 8√3

sin 30=bd/8
1/2=bd/8
bd=4
sesuai rumus pytagoras
[tex]8 = \sqrt{4 {}^{2} + ab {}^{2} } \\ ab {}^{2} = 48 \\ ab = \sqrt{48} = 4 \sqrt{3} [/tex]
luas
[tex]4 \sqrt{3 } \times 4 \div 2 = 8 \sqrt{3} [/tex]