tolong yg jenius jawab dong.... pake jalan yah.....nanti kubuat jadi jawaban terbaik.... cuman nomor 5 ajah

smoga membantu
maaf aku cuman jawab yg b aja

5a)
[tex] \frac{ 3^ {n+12}. 9^{2n-7} }{ 3^{5n} } \\ = \frac{(3^ {n+12}). ( 3^{2})^{2n-7} }{ 3^{5n} } \\ =\frac{(3^ {n+12}). ( 3^{4n-14}) }{ 3^{5n} } \\ = \frac{ 3^{(n+12)+(4n-14)} }{ 3^{5n} } \\ = \frac{ 3^{5n-2} }{ 3^{5n} } \\ = \frac{ 3^{5n} }{ 3^{5n}. 3^{2} } \\ = \frac{1}{9} [/tex]

5b)
[tex]= \frac{ x^{ a^{2} +b} }{ x^{a+ b^{2} } }. \frac{ x^{ b^{2}+c } }{ x^{b+ c^{2} } }. \frac{ x^{ c^{2}+a } }{ x^{ a^{2} +c} } \\ = \frac{ x^{ a^{2}+b+ b^{2} +c+ c^{2}+a } }{ x^{a+ b^{2}+b+ c^{2} +c+ a^{2} } } \\ = 1[/tex]