mohon jawabnya pake cara

Mapel : Matematika

Bab : Akar dan Pangkat
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[tex] = \frac{2}{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } \\ = \frac{2 \sqrt{6} }{6} \\ = \frac{1}{3} \sqrt{6} [/tex]