Matematika

Pertanyaan

6.800 cl+43 liter+32dm

2 Jawaban

  • Kelas 6 Matematika
    Bab Pengukuran

    6.800 cl + 43 liter + 32 dm³
    = (6.800 : 100) liter + 43 liter + (32 x 1) liter
    = 68 liter + 43 liter + 32 liter
    = 143 liter
  • ≡ penyelesaian :

    1 liter = 100 cl
    1 liter = 1 dm

    ⇒6800 cl + 43 liter + 32 dm
    ⇒( 6800 ÷ 100 ) liter + 43 liter + ( 32 × 1 ) liter
    ⇒( 68 + 43 + 32 ) liter
    ⇒143 liter

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