A= 60° B= C=45° Tentukan perbandingan sisi AB dan BC

[tex] \frac{ab}{sin \: c} = \frac{bc}{sin \: a} \\ \frac{ab}{sin \: 45} = \frac{bc}{sin \: 60} \\ \frac{ab}{ \frac{1 \sqrt{2} }{2} } = \frac{bc}{ \frac{1 \sqrt{3} }{2} } \\ ab \times \frac{1}{2} \sqrt{3} = bc \times \frac{1}{2} \sqrt{2} \\ \frac{ab}{bc} = \frac{ \frac{1}{2} \sqrt{2} }{ \frac{1}{2} \sqrt{3} } \\ \frac{ab}{bc} = \frac{ \sqrt{2} }{ \sqrt{3} } \\ \frac{ab}{bc} = \frac{ \sqrt{6} }{3} [/tex]