32. panjang sisa kawat adalah...

d = √16²+12² = √400 = 20 cm
rusuk tegak = √24²+(20/2)² = √676 = 26 cm

panjang kerangka Limas = 2x(12+16) + 4x26
= 56 + 104
= 160 cm

banyak kerangka = (4x100)/160
= 2 kerangka sisa 80 cm

sisa kawat = 80 cm