Tolong bantu jawab no 23 pake cara yaa

Mapel : Matematika

Bab : Lingkaran
____________

Keliling Juring
= (120/360) x Keliling lingkaran
= (1/3) x 2 x 22/7 x 42
= (1/3) x 44 x 6
= 44 x 2
= 88 cm


Maka panjang kawat minimal
= 88 x 4
= 352 m → Opsi B