tolong jawab ya pake caranya kalo ada

[tex] \frac{aq}{am} = \frac{ap}{ab} \\ \frac{2cm}{5cm} = \frac{xcm}{x + 3.9m} \\ 2cm \times (x + 3.9cm) = xcm \times 5cm \\ 2x + 7.8cm = 5x \\ 5x - 2x = 7.8cm \\ 3x = 7.8cm \\ x = \frac{7.8cm}{3} \\ x = 2.6cm[/tex]
Jadi nilai x adalah 2,6 cm (C)

[tex] \frac{aq}{am } = \frac{ap}{ab} \\ \frac{2}{5} = \frac{x}{x + 3.9} \\ 2(x + 3.9) = 5x \\ 2x + 7.8 = 5x \\ 7.8 = 5x - 2x \\ 7.8 = 3x \\ x = \frac{7.8}{3} \\ = 2.6[/tex]