80°C=...°R 80°C=...°K 80°C=...°R
Fisika
reshaamartha55
Pertanyaan
80°C=...°R
80°C=...°K
80°C=...°R
80°C=...°K
80°C=...°R
2 Jawaban
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1. Jawaban Nabilah2220
[tex] {80}^{o} c = ...r \\ \frac{4}{5} \times 80 = {64}^{o} r \\ \\ {80}^{o} c = ...k \\ k = 80 + 27 \\ = {353}^{o} k \\ \\ {80}^{o} c = ...r \\ \frac{4}{5} \times 80 = {64}^{o} r[/tex]
maaf kalau salah -
2. Jawaban lisanishidqi02p5sgwr
80°c=...°R
t°r=[tex] \frac{4}{5} \div t[/tex]°c
[tex] \frac{4}{5} \times 80 = 64[/tex]°r
80°c=..°k
t°k= t°c+273
=80+273
=353°k
semoga membantu dan benar