bentu krasional [tex] bentuk \: rasional \: dri \: \frac{ 2 \sqrt{2} }{6 - 3 \sqrt{3} } [/tex]

[tex] \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } = \frac{2 \sqrt{2} (6 + 3 \sqrt{3)} }{ {6}^{2} - ( {3 \sqrt{3} )}^{2} } \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{36 - 27} \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{9} \\ = \frac{4 \sqrt{2 } + 2 \sqrt{6} }{3} \\ = \frac{2 \sqrt{2} (2 + \sqrt{3}) }{3} [/tex]