pake cara yak ini soal simulasi : v

garis g

(3,0) dan (0,2)

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)

(y - 0)/(2 - 0) = (x - 3)/(0 - 3)

y/2 = (x - 3)/(-3)

y(-3) = (x - 3)(2)

-3y = 2x - 6

y = -2/3 x + 2

m1 = -2/3

garis l

(1,0)

garis l dan g tegak lurus

maka :

m1 × m2 = -1
-2/3 × m2 = -1
m2 = 3/2


persamaan garis l

y - y1 = m (x - x1)
y - 0 = 3/2 (x - 1)
y = 3/2 x - 3/2
3/2 x - y - 3/2 = 0 (× 2)
3x - 2y - 3 = 0

Jadi persamaan garis l adalah 3x - 2y - 3 = 0 (A)