Matematika

Pertanyaan

bantu jawab
trima kasih
bantu jawab trima kasih

2 Jawaban

  • B. ½√2


    Semoga membantu dan jangan lupa follow
    Gambar lampiran jawaban Yesiafirasari

  • [tex] {( \sqrt{32} )}^{ - \frac{1}{5} } \\ = {( \sqrt{ {2}^{5} } )}^{ - \frac{1}{5} } \\ = {( {2}^{ \frac{5}{2} } )}^{ - \frac{1}{5} } \\ = {2}^{ \frac{5}{2} \times ( - \frac{1}{5} ) } \\ = {2}^{ - \frac{1}{2} } \\ = \frac{1}{ {2}^{ \frac{1}{2} } } \\ = \frac{1}{ \sqrt{2} } \\ = \frac{1}{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{1}{2} \sqrt{2} [/tex]
    Jawabannya B