diketahui polinomial 4x^3+3x^2-16x-12=0.jika akar akarnya x1,x2,x3 tentukan x1^3+x2^3+x3^3

x1³ + x2³ + x3³ = a
x1³ + x2³ = a - x3³

maka ,
a- x3³ + x3³ = a
0 = 0

4x³ + 3x² - 16x - 12 = 0
(x+2)(x-2)(4x+3) = 0

x1 = -2, x2 = 2, x3 = -3/4

(x1)³ + (x2)³ + (x3)³ = (-2)³ + 2³ + (-3/4)³
                                = -8 + 8 + (-3/4)³
                                = -27/64