Materi : Limit Fungsi Kelas / Semeter : 11 / 2 [tex] \lim_{(x+1) \to \ 0}[/tex]    [tex] \frac{ x^{14} - 3 x^{11} +2 x^{3} - 6 }{3 x^{9} +2x+1 } [/tex]

smoga jwabannya dpat mmbantu

Limit ( x + 1) —> 0
[tex] \frac{ {x}^{14} - {3x}^{11} + {2x}^{3} - 6}{ {3x}^{9} + 2x + 1} \\ = \frac{ {6x}^{2} - {33x}^{10} + 14 {x}^{13} }{27 {x}^{8} + 2 } \\ = \frac{6( { - 1)}^{2} - {33( - 1)}^{10} + {14( - 1)}^{13} }{ {27( - 1)}^{8} + 2 } \\ = \frac{6 - 33 - 14}{29} \\ = - \frac{41}{29} [/tex]

Semoga bermanfaat.....
-Prisco