bentuk rasional 2 akar2 / 6-3akar3 adalah

[tex] \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } = \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } \times \frac{6 + 3 \sqrt{3} }{6 + 3 \sqrt{3} } \\ = \frac{2 \sqrt{2 } }{ 36 - 27} \times (6 + 3 \sqrt{3)} \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{9} \\ = \frac{4 \sqrt{2 } + 2\sqrt{6} }{3} [/tex]