Soal Tantangan!!! [tex] \sqrt{2x + 1 \sqrt{2x + 1 \sqrt{2x + 1 \sqrt{...} } } } = n[/tex] sederhanakan nilai n ?

[tex] = \sqrt{2x + 1 \sqrt{2x + 1 \sqrt{2x + 1} } } \\ = \sqrt{ {(2x + 1)}^{2} (2x + 1) \sqrt{2x + 1} } \\ = \sqrt{ {(2x + 1)}^{3} \sqrt{2x + 1} } \\ = \sqrt{ {((2x + 1)}^{3}) ^{2}(2x + 1) } \\ = \sqrt{ {(2x + 1)}^{6} (2x + 1) } \\ = \sqrt{ {(2x + 1)}^{6 + 1} } \\ n= \sqrt{(2x + 1) {}^{7} } [/tex]


n = ²•²•²√(2x + 1)^7
n = ^8√(2x + 1)^7


Semoga membantu... Maaf jika ada salah